(1 / 2) * (1 + (x - 0.5) / 0.5 + (1 / PI) * sin((x - 0.5) / 0.5 * PI))

Percentage Accurate: 4.3% → 98.5%
Time: 19.5s
Alternatives: 3
Speedup: 172.0×

Specification

?
\[0 \leq x \land x \leq 1\]
\[\begin{array}{l} \\ \begin{array}{l} t_0 := \frac{x - 0.5}{0.5}\\ \frac{1}{2} \cdot \left(\left(1 + t\_0\right) + \frac{1}{\mathsf{PI}\left(\right)} \cdot \sin \left(t\_0 \cdot \mathsf{PI}\left(\right)\right)\right) \end{array} \end{array} \]
(FPCore (x)
 :precision binary64
 (let* ((t_0 (/ (- x 0.5) 0.5)))
   (* (/ 1.0 2.0) (+ (+ 1.0 t_0) (* (/ 1.0 (PI)) (sin (* t_0 (PI))))))))
\begin{array}{l}

\\
\begin{array}{l}
t_0 := \frac{x - 0.5}{0.5}\\
\frac{1}{2} \cdot \left(\left(1 + t\_0\right) + \frac{1}{\mathsf{PI}\left(\right)} \cdot \sin \left(t\_0 \cdot \mathsf{PI}\left(\right)\right)\right)
\end{array}
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 3 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 4.3% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_0 := \frac{x - 0.5}{0.5}\\ \frac{1}{2} \cdot \left(\left(1 + t\_0\right) + \frac{1}{\mathsf{PI}\left(\right)} \cdot \sin \left(t\_0 \cdot \mathsf{PI}\left(\right)\right)\right) \end{array} \end{array} \]
(FPCore (x)
 :precision binary64
 (let* ((t_0 (/ (- x 0.5) 0.5)))
   (* (/ 1.0 2.0) (+ (+ 1.0 t_0) (* (/ 1.0 (PI)) (sin (* t_0 (PI))))))))
\begin{array}{l}

\\
\begin{array}{l}
t_0 := \frac{x - 0.5}{0.5}\\
\frac{1}{2} \cdot \left(\left(1 + t\_0\right) + \frac{1}{\mathsf{PI}\left(\right)} \cdot \sin \left(t\_0 \cdot \mathsf{PI}\left(\right)\right)\right)
\end{array}
\end{array}

Alternative 1: 98.5% accurate, 5.5× speedup?

\[\begin{array}{l} \\ \left(\left(\left(1.3333333333333333 \cdot \left(\left(\mathsf{PI}\left(\right) \cdot \mathsf{PI}\left(\right)\right) \cdot x\right)\right) \cdot x\right) \cdot x\right) \cdot 0.5 \end{array} \]
(FPCore (x)
 :precision binary64
 (* (* (* (* 1.3333333333333333 (* (* (PI) (PI)) x)) x) x) 0.5))
\begin{array}{l}

\\
\left(\left(\left(1.3333333333333333 \cdot \left(\left(\mathsf{PI}\left(\right) \cdot \mathsf{PI}\left(\right)\right) \cdot x\right)\right) \cdot x\right) \cdot x\right) \cdot 0.5
\end{array}
Derivation
  1. Initial program 4.2%

    \[\frac{1}{2} \cdot \left(\left(1 + \frac{x - 0.5}{0.5}\right) + \frac{1}{\mathsf{PI}\left(\right)} \cdot \sin \left(\frac{x - 0.5}{0.5} \cdot \mathsf{PI}\left(\right)\right)\right) \]
  2. Add Preprocessing
  3. Step-by-step derivation
    1. lift-*.f64N/A

      \[\leadsto \color{blue}{\frac{1}{2} \cdot \left(\left(1 + \frac{x - \frac{1}{2}}{\frac{1}{2}}\right) + \frac{1}{\mathsf{PI}\left(\right)} \cdot \sin \left(\frac{x - \frac{1}{2}}{\frac{1}{2}} \cdot \mathsf{PI}\left(\right)\right)\right)} \]
    2. lift-/.f64N/A

      \[\leadsto \color{blue}{\frac{1}{2}} \cdot \left(\left(1 + \frac{x - \frac{1}{2}}{\frac{1}{2}}\right) + \frac{1}{\mathsf{PI}\left(\right)} \cdot \sin \left(\frac{x - \frac{1}{2}}{\frac{1}{2}} \cdot \mathsf{PI}\left(\right)\right)\right) \]
    3. metadata-evalN/A

      \[\leadsto \color{blue}{\frac{1}{2}} \cdot \left(\left(1 + \frac{x - \frac{1}{2}}{\frac{1}{2}}\right) + \frac{1}{\mathsf{PI}\left(\right)} \cdot \sin \left(\frac{x - \frac{1}{2}}{\frac{1}{2}} \cdot \mathsf{PI}\left(\right)\right)\right) \]
    4. *-commutativeN/A

      \[\leadsto \color{blue}{\left(\left(1 + \frac{x - \frac{1}{2}}{\frac{1}{2}}\right) + \frac{1}{\mathsf{PI}\left(\right)} \cdot \sin \left(\frac{x - \frac{1}{2}}{\frac{1}{2}} \cdot \mathsf{PI}\left(\right)\right)\right) \cdot \frac{1}{2}} \]
    5. lower-*.f644.2

      \[\leadsto \color{blue}{\left(\left(1 + \frac{x - 0.5}{0.5}\right) + \frac{1}{\mathsf{PI}\left(\right)} \cdot \sin \left(\frac{x - 0.5}{0.5} \cdot \mathsf{PI}\left(\right)\right)\right) \cdot 0.5} \]
  4. Applied rewrites4.2%

    \[\leadsto \color{blue}{\left(\frac{\sin \left(\mathsf{PI}\left(\right) \cdot \mathsf{fma}\left(x, 2, -1\right)\right)}{\mathsf{PI}\left(\right)} + \left(x \cdot 2 - 0\right)\right) \cdot 0.5} \]
  5. Taylor expanded in x around 0

    \[\leadsto \color{blue}{\left(x \cdot \left(2 + \left(2 \cdot \cos \left(-1 \cdot \mathsf{PI}\left(\right)\right) + x \cdot \left(-2 \cdot \left(\mathsf{PI}\left(\right) \cdot \sin \left(-1 \cdot \mathsf{PI}\left(\right)\right)\right) + \frac{-4}{3} \cdot \left(x \cdot \left({\mathsf{PI}\left(\right)}^{2} \cdot \cos \left(-1 \cdot \mathsf{PI}\left(\right)\right)\right)\right)\right)\right)\right) + \frac{\sin \left(-1 \cdot \mathsf{PI}\left(\right)\right)}{\mathsf{PI}\left(\right)}\right)} \cdot \frac{1}{2} \]
  6. Applied rewrites98.4%

    \[\leadsto \color{blue}{\left(\left(\left(1.3333333333333333 \cdot \left(\left(\mathsf{PI}\left(\right) \cdot \mathsf{PI}\left(\right)\right) \cdot x\right)\right) \cdot x\right) \cdot x\right)} \cdot 0.5 \]
  7. Add Preprocessing

Alternative 2: 98.5% accurate, 6.6× speedup?

\[\begin{array}{l} \\ \left(x \cdot x\right) \cdot \left(0.6666666666666666 \cdot \left(x \cdot \left(\mathsf{PI}\left(\right) \cdot \mathsf{PI}\left(\right)\right)\right)\right) \end{array} \]
(FPCore (x)
 :precision binary64
 (* (* x x) (* 0.6666666666666666 (* x (* (PI) (PI))))))
\begin{array}{l}

\\
\left(x \cdot x\right) \cdot \left(0.6666666666666666 \cdot \left(x \cdot \left(\mathsf{PI}\left(\right) \cdot \mathsf{PI}\left(\right)\right)\right)\right)
\end{array}
Derivation
  1. Initial program 4.2%

    \[\frac{1}{2} \cdot \left(\left(1 + \frac{x - 0.5}{0.5}\right) + \frac{1}{\mathsf{PI}\left(\right)} \cdot \sin \left(\frac{x - 0.5}{0.5} \cdot \mathsf{PI}\left(\right)\right)\right) \]
  2. Add Preprocessing
  3. Taylor expanded in x around 0

    \[\leadsto \color{blue}{\frac{1}{2} \cdot \frac{\sin \left(-1 \cdot \mathsf{PI}\left(\right)\right)}{\mathsf{PI}\left(\right)} + x \cdot \left(\frac{1}{2} \cdot \left(2 + 2 \cdot \cos \left(-1 \cdot \mathsf{PI}\left(\right)\right)\right) + x \cdot \left(-1 \cdot \left(\mathsf{PI}\left(\right) \cdot \sin \left(-1 \cdot \mathsf{PI}\left(\right)\right)\right) + \frac{-2}{3} \cdot \left(x \cdot \left({\mathsf{PI}\left(\right)}^{2} \cdot \cos \left(-1 \cdot \mathsf{PI}\left(\right)\right)\right)\right)\right)\right)} \]
  4. Applied rewrites98.3%

    \[\leadsto \color{blue}{\left(x \cdot x\right) \cdot \left(\left(\left(x \cdot 0.6666666666666666\right) \cdot \mathsf{PI}\left(\right)\right) \cdot \mathsf{PI}\left(\right)\right)} \]
  5. Step-by-step derivation
    1. Applied rewrites98.4%

      \[\leadsto \left(x \cdot x\right) \cdot \left(0.6666666666666666 \cdot \color{blue}{\left(x \cdot \left(\mathsf{PI}\left(\right) \cdot \mathsf{PI}\left(\right)\right)\right)}\right) \]
    2. Add Preprocessing

    Alternative 3: 67.8% accurate, 172.0× speedup?

    \[\begin{array}{l} \\ 0 \end{array} \]
    (FPCore (x) :precision binary64 0.0)
    double code(double x) {
    	return 0.0;
    }
    
    real(8) function code(x)
        real(8), intent (in) :: x
        code = 0.0d0
    end function
    
    public static double code(double x) {
    	return 0.0;
    }
    
    def code(x):
    	return 0.0
    
    function code(x)
    	return 0.0
    end
    
    function tmp = code(x)
    	tmp = 0.0;
    end
    
    code[x_] := 0.0
    
    \begin{array}{l}
    
    \\
    0
    \end{array}
    
    Derivation
    1. Initial program 4.2%

      \[\frac{1}{2} \cdot \left(\left(1 + \frac{x - 0.5}{0.5}\right) + \frac{1}{\mathsf{PI}\left(\right)} \cdot \sin \left(\frac{x - 0.5}{0.5} \cdot \mathsf{PI}\left(\right)\right)\right) \]
    2. Add Preprocessing
    3. Taylor expanded in x around 0

      \[\leadsto \color{blue}{\frac{1}{2} \cdot \frac{\sin \left(-1 \cdot \mathsf{PI}\left(\right)\right)}{\mathsf{PI}\left(\right)}} \]
    4. Step-by-step derivation
      1. associate-*r/N/A

        \[\leadsto \color{blue}{\frac{\frac{1}{2} \cdot \sin \left(-1 \cdot \mathsf{PI}\left(\right)\right)}{\mathsf{PI}\left(\right)}} \]
      2. *-commutativeN/A

        \[\leadsto \frac{\color{blue}{\sin \left(-1 \cdot \mathsf{PI}\left(\right)\right) \cdot \frac{1}{2}}}{\mathsf{PI}\left(\right)} \]
      3. associate-/l*N/A

        \[\leadsto \color{blue}{\sin \left(-1 \cdot \mathsf{PI}\left(\right)\right) \cdot \frac{\frac{1}{2}}{\mathsf{PI}\left(\right)}} \]
      4. mul-1-negN/A

        \[\leadsto \sin \color{blue}{\left(\mathsf{neg}\left(\mathsf{PI}\left(\right)\right)\right)} \cdot \frac{\frac{1}{2}}{\mathsf{PI}\left(\right)} \]
      5. sin-negN/A

        \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sin \mathsf{PI}\left(\right)\right)\right)} \cdot \frac{\frac{1}{2}}{\mathsf{PI}\left(\right)} \]
      6. sin-PIN/A

        \[\leadsto \left(\mathsf{neg}\left(\color{blue}{0}\right)\right) \cdot \frac{\frac{1}{2}}{\mathsf{PI}\left(\right)} \]
      7. metadata-evalN/A

        \[\leadsto \color{blue}{0} \cdot \frac{\frac{1}{2}}{\mathsf{PI}\left(\right)} \]
      8. mul0-lft66.0

        \[\leadsto \color{blue}{0} \]
    5. Applied rewrites66.0%

      \[\leadsto \color{blue}{0} \]
    6. Add Preprocessing

    Reproduce

    ?
    herbie shell --seed 1 
    (FPCore (x)
      :name "(1 / 2) * (1 + (x - 0.5) / 0.5 + (1 / PI) * sin((x - 0.5) / 0.5 * PI))"
      :precision binary64
      :pre (and (<= 0.0 x) (<= x 1.0))
      (* (/ 1.0 2.0) (+ (+ 1.0 (/ (- x 0.5) 0.5)) (* (/ 1.0 (PI)) (sin (* (/ (- x 0.5) 0.5) (PI)))))))