?

Average Error: 0 → 0
Time: 1.7s
Precision: binary64
Cost: 64

?

\[-1.79 \cdot 10^{+308} \leq x \land x \leq 1.79 \cdot 10^{+308}\]
\[x \]
\[x \]
(FPCore (x) :precision binary64 x)
(FPCore (x) :precision binary64 x)
double code(double x) {
	return x;
}
double code(double x) {
	return x;
}
real(8) function code(x)
    real(8), intent (in) :: x
    code = x
end function
real(8) function code(x)
    real(8), intent (in) :: x
    code = x
end function
public static double code(double x) {
	return x;
}
public static double code(double x) {
	return x;
}
def code(x):
	return x
def code(x):
	return x
function code(x)
	return x
end
function code(x)
	return x
end
function tmp = code(x)
	tmp = x;
end
function tmp = code(x)
	tmp = x;
end
code[x_] := x
code[x_] := x
x
x

Error?

Try it out?

Your Program's Arguments

Results

Enter valid numbers for all inputs

Derivation?

  1. Initial program 0

    \[x \]
  2. Final simplification0

    \[\leadsto x \]

Reproduce?

herbie shell --seed 1 
(FPCore (x)
  :name "x"
  :precision binary64
  :pre (and (<= -1.79e+308 x) (<= x 1.79e+308))
  x)