?

Average Error: 0.9 → 0.3
Time: 5.2s
Precision: binary64
Cost: 6592

?

\[0.01 \leq x \land x \leq 708\]
\[\frac{e^{x} - 1}{x} \]
\[\frac{\mathsf{expm1}\left(x\right)}{x} \]
(FPCore (x) :precision binary64 (/ (- (exp x) 1.0) x))
(FPCore (x) :precision binary64 (/ (expm1 x) x))
double code(double x) {
	return (exp(x) - 1.0) / x;
}
double code(double x) {
	return expm1(x) / x;
}
public static double code(double x) {
	return (Math.exp(x) - 1.0) / x;
}
public static double code(double x) {
	return Math.expm1(x) / x;
}
def code(x):
	return (math.exp(x) - 1.0) / x
def code(x):
	return math.expm1(x) / x
function code(x)
	return Float64(Float64(exp(x) - 1.0) / x)
end
function code(x)
	return Float64(expm1(x) / x)
end
code[x_] := N[(N[(N[Exp[x], $MachinePrecision] - 1.0), $MachinePrecision] / x), $MachinePrecision]
code[x_] := N[(N[(Exp[x] - 1), $MachinePrecision] / x), $MachinePrecision]
\frac{e^{x} - 1}{x}
\frac{\mathsf{expm1}\left(x\right)}{x}

Error?

Try it out?

Your Program's Arguments

Results

Enter valid numbers for all inputs

Derivation?

  1. Initial program 0.9

    \[\frac{e^{x} - 1}{x} \]
  2. Simplified0.3

    \[\leadsto \color{blue}{\frac{\mathsf{expm1}\left(x\right)}{x}} \]
    Proof

    [Start]0.9

    \[ \frac{e^{x} - 1}{x} \]

    expm1-def [=>]0.3

    \[ \frac{\color{blue}{\mathsf{expm1}\left(x\right)}}{x} \]
  3. Final simplification0.3

    \[\leadsto \frac{\mathsf{expm1}\left(x\right)}{x} \]

Alternatives

Alternative 1
Error50.9
Cost832
\[\left(1 + \left(x \cdot 0.5 + \frac{1}{x}\right)\right) + \frac{-1}{x} \]
Alternative 2
Error50.9
Cost320
\[1 + x \cdot 0.5 \]
Alternative 3
Error53.2
Cost64
\[1 \]

Error

Reproduce?

herbie shell --seed 1 
(FPCore (x)
  :name "(exp(x)-1)/x"
  :precision binary64
  :pre (and (<= 0.01 x) (<= x 708.0))
  (/ (- (exp x) 1.0) x))