Average Error: 0 → 0
Time: 5.4s
Precision: 64
\[{t}^{5}\]
\[{t}^{5}\]
{t}^{5}
{t}^{5}
double f(double t) {
        double r569636 = t;
        double r569637 = 5.0;
        double r569638 = pow(r569636, r569637);
        return r569638;
}

double f(double t) {
        double r569639 = t;
        double r569640 = 5.0;
        double r569641 = pow(r569639, r569640);
        return r569641;
}

Error

Bits error versus t

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Derivation

  1. Initial program 0

    \[{t}^{5}\]
  2. Final simplification0

    \[\leadsto {t}^{5}\]

Reproduce

herbie shell --seed 1 
(FPCore (t)
  :name "pow(t,5)"
  :precision binary64
  (pow t 5))